Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 11 - Other Chi-Square Tests - 11-2 Testing Using Contingency Tables - Exercises 11-2 - Page 634: 10

Answer

10. Step 1: $H_0$ : The rank of officers in the military is independent from the branch of the Armed Forces. $H_1$: The rank of officers in the military is dependent upon the branch of the Armed Forces. Step 2: Since α=0.05, the critical value using Table G with (4-1)(2-1) = (3)(1) =3 degrees of freedom is 7.815. Step 3: Expected Value: $E_1,1$ = $\frac{(73282)(31358)}{(200468)}$ = 11463.06 $E_1,2$ = $\frac{(73282)(169110)}{(200468)}$ = 61818.94 $E_2,1$ = $\frac{(50566)(31358)}{(200468)}$= 7909.73 $E_2,2$ = $\frac{(50566)(169110)}{(200468)}$ = 42656.27 $E_3,1$ = $\frac{(10457)(31358)}{(200468)}$ = 1635.73 $E_3,2$ = $\frac{(10457)(169110)}{(200468)}$ = 8821.27 $E_4,1$ = $\frac{(66163)(31358)}{(200468)}$ = 10349.48 $E_4,2$ = $\frac{(66163)(169110)}{(200468)}$ = 55813.52 Test Value : χ2 = Σ $\frac{(O-E)^{2}}{E}$ = $\frac{(10791-11.463.06)^{2}}{11463.06}$ + $\frac{(62491-61818.94)^{2}}{61818.94}$ + $\frac{(7816-7909.73)^{2}}{7909.73}$ + $\frac{(42750-42656.27)^{2}}{45656.27}$ + $\frac{(932-1635.73)^{2}}{1635.73}$ + $\frac{(9525-8821.27)^{2}}{8821.27}$ + $\frac{(11819-10349.48)^{2}}{10349.48}$ + $\frac{(54344-55813.52)^{2}}{55813.52}$ =39.402+7.306+1.111+0.206+302.758+56.140+208.657+38.691 =654.272 Step 4: Since 654.272 > 7.815, the decision is to reject the null hypothesis. Step 5: There is enough evidence to claim that the rank of officers in the military is dependent upon the branch of the Armed Forces.
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