Elementary Statistics: A Step-by-Step Approach with Formula Card 9th Edition

Published by McGraw-Hill Education
ISBN 10: 0078136334
ISBN 13: 978-0-07813-633-7

Chapter 11 - Other Chi-Square Tests - 11-2 Testing Using Contingency Tables - Exercises 11-2 - Page 634: 14

Answer

14. Step 1: $H_0$ : The state and the political party affiliation are independent from each other. $H_1$: The state and the political party affiliation are dependent upon each other. Step 2: Since α=0.05, the critical value using Table G with (4-1)(2-1) = (3)(1) =3 degrees of freedom is 7.815. Step 3: Expected Value: $E_1,1$ = $\frac{(72)(53)}{(134)}$ = 28.48 $E_1,2$ = $\frac{(72)(27)}{(134)}$ = 14.51 $E_1,3$ = $\frac{(72)(18)}{(134)}$= 9.67 $E_1,4$ = $\frac{(72)(36)}{(134)}$ = 19.34 $E_2,1$ = $\frac{(62)(53)}{(134)}$ = 24.52 $E_2,2$ = $\frac{(62)(27)}{(134)}$ = 12.49 $E_2,3$ = $\frac{(62)(18)}{(134)}$ = 8.33 $E_2,4$ = $\frac{(62)(36)}{(134)}$ = 16.66 Test Value : χ2 = Σ $\frac{(O-E)^{2}}{E}$ = $\frac{(38-28.48)^{2}}{28.48}$ + $\frac{(10-14.51)^{2}}{14.51}$ + $\frac{(12-9.67)^{2}}{9.67}$ + $\frac{(12-19.34)^{2}}{19.34}$ + $\frac{(15-24.52)^{2}}{24.52}$ + $\frac{(17-12.49)^{2}}{12.49}$ + $\frac{(6-8.33)^{2}}{8.33}$ + $\frac{(24-16.66)^{2}}{16.66}$ =3.184+1.4+0.561+2.788+3.698+1.626+0.651+3.237 =17.145 Step 4: Since 17.145 > 7.815, the decision is to reject the null hypothesis. Step 5: There is enough evidence to claim that the state and the political party affiliation are dependent upon each other.
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