## Elementary Statistics (12th Edition)

Published by Pearson

# Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts: 9

#### Answer

Variance:$195.8 \ (m\$)^2$. Standard deviation:$13.99 \ m\$$Range:54 \ m\$$.

#### Work Step by Step

By using the results from before: $\mu=16.36 \ m\$.$Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(58-16.36)^2+(22-16.36)^2+...+(4-16.36)^2}{14}=195.8 \ (m\$)^2.$ Standard deviation=$\sqrt{variance}=\sqrt{195.8 \ (m\$)^2}=13.99 \ m\$$Range=maximum value-minimum value=58 \ m\-4 \ m\=54 \ m\$$.

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