Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts: 10

Answer

Variance:$91.01\ (deaths)^2$. Standard deviation:$9.54 \ deaths$ Range:$28 \ deaths$.

Work Step by Step

By using the results from before: $\mu=82.7 \ deaths.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(78-82.7)^2+(81-82.7)^2+...+(97-82.7)^2}{10}=91.01\ (deaths)^2.$ Standard deviation=$\sqrt{variance}=\sqrt{91.01\ (deaths)^2}=9.54 \ deaths$ Range=maximum value-minimum value=$97 \ deaths-69 \ deaths=28 \ deaths$.
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