Answer
Variance:$91.01\ (deaths)^2$.
Standard deviation:$9.54 \ deaths$
Range:$28 \ deaths$.
Work Step by Step
By using the results from before: $\mu=82.7 \ deaths.$
Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(78-82.7)^2+(81-82.7)^2+...+(97-82.7)^2}{10}=91.01\ (deaths)^2.$
Standard deviation=$\sqrt{variance}=\sqrt{91.01\ (deaths)^2}=9.54 \ deaths$
Range=maximum value-minimum value=$97 \ deaths-69 \ deaths=28 \ deaths$.
