Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts: 5

Answer

Variance:$9493.16(million \$)^2.$ Standard deviation:$97.43 \ million \$$ Range:265m\$.

Work Step by Step

By using the results from before: $\mu=159.8 \ million.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(332m-159.8m)^2+(302m-159.8m)^2+...+(67m-159.8m)^2}{10}=9493.16(million \$)^2.$ Standard deviation=$\sqrt{variance}=\sqrt{9493.16(million \$)^2}=97.43 \ million \$$ Range=maximum value-minimum value=332m\$-67m\$=265m\$.
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