Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.3 - Three-Dimensional Coordinate Geometry - 9.3 Exercises - Page 652: 6

Answer

$D = \sqrt {118}$ See graph below.

Work Step by Step

Given P (5, -4, -6) and Q (8, -7, 4), the question asks for a graph of the two points and the distance between them. See graph below (graphed with GeoGebra) The distance between the two points is determined by the distance formula: $D = \sqrt {(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2 }$ $D = \sqrt {(8 - 5)^2 + (-7 - (-4))^2 + (4 - (-6))^2 }$ $D = \sqrt {9 + 9 + 100 }$ $D = \sqrt {118}$
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