Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.3 - Three-Dimensional Coordinate Geometry - 9.3 Exercises - Page 652: 3

Answer

See graph below. $D = \sqrt {42}$

Work Step by Step

Given P (3,1,0) and Q (-1, 2, -5), the question asks for a graph of the two points and the distance between them. See graph below (graphed with GeoGebra) The distance between the two points is determined by the distance formula: $D = \sqrt {(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2 }$ $D = \sqrt {(-1 - 3)^2 + (2 - 1)^2 + (-5 - 0)^2 }$ $D = \sqrt {16 + 1 + 25}$ $D = \sqrt {42}$
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