Answer
center $(6, 1, 0)$, radius $\sqrt{37}$
Work Step by Step
$x^2+y^2+z^2=12x+2y$
$x^2-12x+y^2-2y+z^2=0$
$x^2-12x+(\frac{-12}{2})^2+y^2-2y+(\frac{-2}{2})^2+z^2=0+(\frac{-12}{2})^2+(\frac{-2}{2})^2$
$x^2-12x+36+y^2-2y+1+z^2=36+1$
$(x-6)^2+(y-1)^2+z^2=37$
This is a sphere with center $(6, 1, 0)$ and radius $\sqrt{37}$.
