Answer
(a) $2822lb$
(b) $2779lb$
Work Step by Step
Use the figure given in the previous problem and imagine a different incline angle.
(a) Assume the weight of the car is $W$, the force component along the incline by this weight is $Wsin\theta$.
Given $\theta=10^{\circ}$ and a value of $490lb$ for this force, we have $Wsin10^{\circ}=490$ which gives $W\approx2822lb$
(b) The force $F$ the car exerts against the driveway equals to the other component of the weight normal to the surface and is given by $F=Wcos10^{\circ}\approx2779lb$
