Answer
$5000 \sqrt 3 ft-lbs$
Work Step by Step
Given the force $D = <200, 0>$, a 50 lb force, and an angle of 30 degrees from the horizontal.
The question asks for the work done in foot-pounds.
Work is equal to the dot product of the Force Vectors and Distance Vectors
Force is 50 lbs, but it is separated into its vertical and horizontal components
Thus W = * D
$W = <50 \cos 30, 50 \sin 30> * <200, 0>$
$50 \cos 30 * 200 + 50 \sin 30 * 0 $
$5000 \sqrt 3 ft-lbs$
