Answer
$259890 ft-lbs$
Work Step by Step
Given the force $D = <0, 500>$, a 2500 lb force due to gravity, and an angle of 12 degrees from the horizontal.
The question asks for the work done in foot-pounds.
Work is equal to the dot product of the Force Vectors and Distance Vectors
Force is 2500 lbs, but it is separated into its vertical and horizontal components
Thus $W = * D$
$W = <2500 \cos 12, 2500 \sin 12> * <0, 500>$
$0 + 2500 \sin 12 * 500 $
$259890 ft-lbs$
