Answer
graph 1
Work Step by Step
When $t=\pi\times n$ then $sin (t)=0$ so
$x=\sin \left( t+\sin t\right) =\sin \left( \pi n+\sin \pi n\right) =\sin \left( \pi n+0\right) =0$
And $y=\cos \left( \pi n+\cos \pi n\right) =\cos \left( \pi n\pm 1\right) \neq 0$
So we see that when $x=0$ $y\ne 0$ so this graph doesnt pass from origin (0,0) and graph 1 fits only to this condition
