Answer
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Work Step by Step
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Maximum value of $x $ will be $sin1 \approx 0.84147$ becouse $cos( t) $ can be 1 maximum ad becouse $0\leq t \leq 2\pi $ minimal value of $cos (t) $ in that interval can be $-1$ so the minimum value of $x$ will be$-sin1\approx -0.84147$
For y
$0\leq t \leq 2\pi $ then $0\leq t^{3/2}\leq \left( 2\pi \right) ^{3/2}$
İn that interval maximum and minimum values of $y$ are 1 and $-1$ respectively
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