Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 523: 53

Answer

The land would cost about $165,554

Work Step by Step

First, one must find the area using Heron's formula: $\sqrt{s(s-a)(s-b)(s-c)}$, where $s$ is half of the perimeter of the triangle: $s=\frac{1}{2}(a+b+c)$ $s=\frac{1}{2}(112+148+190)=\frac{1}{2}(450)=225$ Now, we can find the area: $A=\sqrt{225(225-112)(225-148)(225-190)}$ $A=\sqrt{225(113)(77)(35)}$ $A=\sqrt{68,520,375}\approx8278$ ft$^2$ Since the land is valued at \$20 per ft$^2$, using $\frac{\$20}{1ft^2}=\frac{?}{8278 ft^2}$ will determine the land's value: $8278\cdot \$20= \$165,554$
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