Answer
161 ft
Work Step by Step
Step 1. Draw a diagram as shown. T is the top, Q is the base of the tower, P is the anchor point.
Step 2. In the triangle of TPQ, angle $\angle TQP=90+32=122^{\circ}$, use the Law of Cosines, we have
$x^2=125^2+55^2-2\times125\times55\times cos122^{\circ}$ which gives $x\approx161ft$
