Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 522: 49

Answer

The distance between the kites is approximately $401$ft

Work Step by Step

To find the distance (which we'll assign the variable $x$), the law of cosines should be used: $x^2=380^2+420^2-2(380)(420)\cdot $cos$(30º)$ $x^2=144,400+176,400-319,200\cdot 1/2$ $x^2=320,800-159,600$ $x=\sqrt{161,200}$ $x\approx401$ft
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