Answer
$θ\approx31.17º$
Work Step by Step
The angle we can to find opposite to is the one that is 120ft long, so:
$120^2=212^2+230^2-2(212)(230)\cdot $cos$(θ)$
$14'400=44'944+52'900-97'520\cdot $cos$(θ)$
$14'400-44'944-52'900=-97'520\cdot $cos$(θ)$
$14'400-44'944-52'900=-97'520\cdot $cos$(θ)$
$-83'444=-97'520\cdot $cos$(θ)$
cos$(θ)=\frac{-83'444}{-97'520}$
$θ=$cos$^{-1}\frac{-83'444}{-97'520}$
$θ\approx31.17º$