Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.6 - The Law of Cosines - 6.6 Exercises - Page 523: 51

Answer

The shortest length of cable needed is 3835ft long

Work Step by Step

To find the length of the cable, one must first find $x$ (see picture). $x$ can be found using the sine function: sin$(74º)=\frac{3400}{x}$ $x=\frac{3400}{sin(74º)}\approx3537$ft Now, one has all the data to find the length of the cable (variable $l$ will be used) using the law of cosines: $l^2=800^2+3537^2-2(800)(3537)\cdot $cos$(106º)$ $l^2=640,000+12,510,369-5,659,200\cdot (-0.28)$ $l^2=13,150,369+1,559,887$ $l=\sqrt{14,710,256}$ $l \approx 3835$ft
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