Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.5 - The Law of Sines - 6.5 Exercises - Page 514: 33

Answer

$$219 \space ft$$

Work Step by Step

$$\angle A + \angle B + \angle C = 180^o$$ $$82^o + 52^o + \angle C= 180^o$$ $$\angle C = 180^o -82^o - 52^o = 46^o$$ The distance from A to C is represented by $b$ on the drawing. Therefore, we can use the law of sines to calculate its value: $$\frac{sin \space B}{b} = \frac{sin \space C} c$$ $$c \space sin \space B = b \space sin \space C$$ $$c \space \frac{sin \space B}{sin \space C} = b$$ $$b = c \space \frac{sin \space B}{sin \space C} = (200 \space ft) \frac{sin \space 52^o}{sin \space 46^o} = 219 \space ft$$
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