Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.5 - The Law of Sines - 6.5 Exercises - Page 514: 15

Answer

$ \angle B=85^{\circ}$ $a=5$ and $c=9.1$

Work Step by Step

I. Need to find the last angle. $30^{\circ}+\angle B+65^{\circ}=180^{\circ}$ $\implies \angle B=85^{\circ}$ II. Use law of sines formula to find $a$ and $b$ $\dfrac{\sin 30^{\circ}}{a}=\dfrac{\sin 85^{\circ} }{10}=\dfrac{\sin 65^{\circ} }{c}$ This implies that $a=\dfrac{10 \sin 30^{\circ} }{\sin 85^{\circ}}=5$ and $c=\dfrac{10 \sin 65^{\circ} }{\sin 85^{\circ}}=9.1$
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