Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.5 - The Law of Sines - 6.5 Exercises - Page 513: 8

Answer

$$x \approx 145$$

Work Step by Step

1. Find the last angle. $$102 ^{o} + 28^o + C = 180^o$$ $$C = 180^o - 102^o - 28^o = 50^o$$ 2. Use the law of sines to calculate $x$: $$\frac{sin \space 50^o}{x} = \frac{sin \space 102^o}{185}$$ $$x = \frac{sin \space 50 ^o}{sin \space 102^o} \times 185$$ $$x \approx 145 \space (Calculator)$$
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