Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.5 - The Law of Sines - 6.5 Exercises - Page 513: 3

Answer

$x\approx318.76$

Work Step by Step

The triangle is shown in the attached image below. Angles $A$ and $B$ are known. Since $\angle A+\angle B+\angle C=180^{\circ}$, substitute the known angles into the formula and solve for $\angle C$: $\angle C=180^{\circ}-24.6^{\circ}-98.4^{\circ}=57^{\circ}$ Substitute the known values into the formula $\dfrac{\sin A}{a}=\dfrac{\sin C}{x}$, obtained from the Law of Sines and solve for $x$ to find the unknown side: $\dfrac{\sin98.4^{\circ}}{376}=\dfrac{\sin57^{\circ}}{x}$ $\dfrac{376}{\sin98.4^{\circ}}=\dfrac{x}{\sin57^{\circ}}$ $x=\Big(\dfrac{\sin57^{\circ}}{\sin98.4^{\circ}}\Big)376\approx318.76$
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