Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.5 - The Law of Sines - 6.5 Exercises - Page 513: 4

Answer

$x\approx25.43$

Work Step by Step

The triangle is shown in the attached image below. Angles $A$ and $B$ are known. Since $\angle A+\angle B+\angle C=180^{\circ}$, substitute the known angles into the formula and solve for $\angle C$: $\angle C=180^{\circ}-37.5^{\circ}-28.1^{\circ}=114.4^{\circ}$ Substitute the known values into the formula $\dfrac{\sin A}{a}=\dfrac{\sin C}{x}$, obtained from the Law of Sines and solve for the unknown side $x$: $\dfrac{\sin37.5^{\circ}}{17}=\dfrac{\sin114.4^{\circ}}{x}$ $\dfrac{17}{\sin37.5^{\circ}}=\dfrac{x}{\sin114.4^{\circ}}$ $x=\Big(\dfrac{\sin114.4^{\circ}}{\sin37.5^{\circ}}\Big)17\approx25.43$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.