Answer
$4362$ years
Work Step by Step
Use the radioactive decay model with equation $m(t)=m_0\cdot 2^{-t/h}$ with the given conditions $m(t)=0.59m_0,h=5730$, we have $0.59m_0=m_0\cdot 2^{-t/5730}$ which gives $t=-5730\times log_20.59\approx4362$ years
