Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.6 - Modeling with Exponential Functions - 4.6 Exercises - Page 380: 15

Answer

(a) $n(t)=29.76e^{0.012936t}$ (b) $53.6$ years (c) $38.55$ million

Work Step by Step

(a) Use the exponential model equation $n(t)=n_0e^{rt}$ and the given conditions $n_0=29.76, n(10)=33.87$, we have $33.87=29.76e^{10r}$ which gives $r=ln(33.87/29.76)/10\approx0.012936$ thus the model equation can be written as $n(t)=29.76e^{0.012936t}$ (b) Let $n(t)=2n_0$, we get $2n_0=n_0e^{0.0129t}$ so that $t=ln2/0.012936\approx53.6$ years (c) As 2010 corresponds to $t=20$, we have $n(20)=29.76e^{0.012936\times20}\approx38.55$ million
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