Answer
$149$ hours
Work Step by Step
Use the exponential decay formula $m(t)=m_0\cdot 2^{-t/h}$ together with the
conditions given $m_0=250,m(48)=200,t=48$, we have $200=250\times 2^{-48/h}$ which gives $h=-48/(log_2(200/250))\approx149$ hours
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 4 - Section 4.6 - Modeling with Exponential Functions - 4.6 Exercises - Page 380: 21
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