Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 253: 60

Answer

$(a)$ $A=-\frac{5}{2}x^2+375x$ $(b)$ $A=14062.5ft^2$

Work Step by Step

Let the length of the rectangle be $x$ $ft$. So, including all the parallel divisions and the $2$ side of the rectangle (which are $xft$), we have fencing of $5xft$ Width of the rectangle will be $\frac{750-5x}{2}ft$ Given the above information, we have the total area of rectangle : $A=x\times \frac{750-5x}{2}=\frac{-5x^2+750x}{2}=-\frac{5}{2}x^2+375x$ $a=-2.5$ $b=375$ Since the value of $a$ is negative, we have maximum value of the function at $x=-\frac{b}{2a}$ $x=-\frac{375}{-2.5\times2}=\frac{375}{5}=75$ Length is $75ft$ Width is $\frac{750-5\times 75}{2}=187.5ft$ So, the largest possible total area of four pens will be : $A=75\times 187.5=14062.5ft^2$
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