Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 253: 54

Answer

maximum profit $P(x)=4950$ cans of soda $x=1500$

Work Step by Step

Calculate the maximum of the function by substituting the values from the function into $x_{MAX}=\frac{-b}{2a}\rightarrow x_{MAX}=1500$ which is the number of cans of soda. Then substitute $x=1500$ into the function to get the maximum profit.
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