Answer
minimum $-\frac{3}{2}$
Work Step by Step
We have $g(x)=2x^2+6x+3=2(x^2+3x)+3=2[(x+\frac{3}{2})^2-\frac{9}{4}]+3=2(x+\frac{3}{2})^2-\frac{3}{2}$
thus a minimum will happen at $x=-\frac{3}{2}$ with a value of $g(-3/2)=-\frac{3}{2}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Review - Test - Page 323: 2
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