Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 320: 5

Answer

$\dfrac{5}{4}$

Work Step by Step

As we are given that $a=-1$ and $a =-1 \lt 1$ and this shows a maximum value at the point $h=\dfrac{-b}{2a}=-\dfrac{3}{2(-1)}=\dfrac{3}{2}$ Now, $f(h)=f(\dfrac{3}{2})=-(\dfrac{3}{2})^2+3(\dfrac{3}{2})-1=-\dfrac{9}{4}+\dfrac{9}{2}-1$ or, $f(\dfrac{3}{2})= \dfrac{5}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.