Answer
0, -1 of multiplicity 3, 1 of multiplicity 2
See graph below.
Work Step by Step
The question asks for the multiplicity of each zero of P(x) and the graph of P(x)
Given $P(x) = x(x+1)^3 (x-1)^2$
The power of the root is the multiplicity
So for $(x+1)^3 = 0$, the multiplicity is 3
For $(x-1)^2 = 0$, the multiplicity is 2
For $x = 0$, x = 0 (and that's it)
See graph below.
