Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 320: 30

Answer

$-x^2-7x-47-\frac{325}{x-7}$

Work Step by Step

Use synthetic divisions as shown in the figure, we can get the quotient and the remainder as: $\frac{-x^3+2x+4}{x-7}=-x^2-7x-47-\frac{325}{x-7}$
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