Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.6 - Transformations of Functions - 2.6 Exercises - Page 207: 59

Answer

$f(x)=\sqrt[4]{-x}+1$

Work Step by Step

Given the standard function, $ f(x)=\sqrt[4]{x} $, the equation of the graph that is reflected about the $y-$axis will have a negative multiplier in the $x-$variable. Hence, the equation becomes \begin{array}{l}\require{cancel} f(x)=\sqrt[4]{-x} .\end{array} Given the function, $ f(x)=\sqrt[4]{-x} $, the equation of the graph that shifts upward will have a positive constant added to the equation. Hence, a shift of $1$ unit upward will have the equation, \begin{array}{l}\require{cancel} f(x)=\sqrt[4]{-x}+1 .\end{array}
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