Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.6 - Transformations of Functions - 2.6 Exercises - Page 207: 58

Answer

$f(x)=-|x-4|+3$

Work Step by Step

Given the standard function, $ f(x)=|x| $, the equation of the graph that is reflected about the $x-$axis will have a negative multiplier in the $y-$variable. Hence, the equation becomes \begin{array}{l}\require{cancel} -f(x)=|x| \\\\ f(x)=-|x| .\end{array} Given the standard function, $ f(x)=-|x| $, the equation of the graph that shifts to the right will have a negative constant added to the $x-$variable. Hence, a shift of $4$ units to the right will have the equation, \begin{array}{l}\require{cancel} f(x)=-|x-4| .\end{array} Given the standard function, $ f(x)=-|x-4| $, the equation of the graph that shifts upward will have a positive constant added to the equation. Hence, a shift of $3$ units up will have the equation, \begin{array}{l}\require{cancel} f(x)=-|x-4|+3 .\end{array}
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