## Precalculus: Mathematics for Calculus, 7th Edition

f(-4) = 8 $f(-\frac{3}{2}) = -\frac{3}{2}$ f(-1) = -1 f(0) = 0 f(25) = -1
for f(-4) , it is less than -1 therefore $f(-4) = (-4)^2 + 2(-4) = 16-8 = 8$ for $f(-\frac{3}{2})$ it less than 1 but greater than -1 therefore $f(-\frac{3}{2})$ = $-\frac{3}{2}$ for f(-1) it is equal to -1 therefore $f(-1) = (-1)^2 + 2(-1) = 1-2 = -1$ for f(0) it is less than 1 but greater than -1 therefore f(0) = 0 for f(25) it is grater than 1 therefore f(25) = -1