Answer
$f(-2)=-12$; $f(-1)=-3$; $f(0)=0$; $f\left(\frac{1}{2}\right)=\frac{9}{8}$
Work Step by Step
$$f(-2)=(-2)^3+2(-2)$$ $$f(-2)=-8-4$$ $$f(-2)=-12$$
$$f(-1)=(-1)^3+2(-1)$$ $$f(-1)=-1-2$$ $$f(-1)=-3$$
$$f(0)=(0)^3+2(0)$$ $$f(0)=0+0$$ $$f(0)=0$$
$$f(\frac{1}{2})=(\frac{1}{2})^3+2(\frac{1}{2})$$ $$f(\frac{1}{2})=\frac{1}{2^3}+\frac{2}{2}$$ $$f(\frac{1}{2})=\frac{1}{8}+1$$ $$f(\frac{1}{2})=\frac{1}{8}+1\times\frac{8}{8}$$ $$f(\frac{1}{2})=\frac{1}{8}+\frac{8}{8}$$ $$f(\frac{1}{2})=\frac{9}{8}$$
