Answer
68 feet is the maximum height
Work Step by Step
Given $h(t) = -16t^2 + 48t + 32$
The maximum height can be determined from its vertex, given here: $\frac{-b}{2a}$ = \frac{-48}{-32} = 1.5
At t=1.5, the height will be at 68 feet
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 2 - Review - Exercises - Page 233: 79
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