Answer
a. $P(10) = 5010$ $P(20) = 7040$
b. Average Rate of Change: $203$
Work Step by Step
$P(t) = 3000 + 200t + 0.1t^2$
a. Find P(10) and P(20)
$P(10) = 3000 + 200 (10) + 0.1 (10)^2 = 5010$
$P(20) = 3000 + 200 (20) + 0.1 (20)^2 = 7040$
This represents the planned seaside community in $1995 (P(10))$ and $2005 (P(20))$
b. Average Rate of Change (from x=10 to x=20): $P = \frac{P(20) - P(10)}{20-10} = \frac{2030}{10} = 203$
