Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 232: 56

Answer

Net Change: $h^2 + 2h + 2ah$ Average Rate of change: $h + 2 + 2a$

Work Step by Step

From the equation $g(x) = (x+1)^2$, we are looking from the net change and average rate of change from x=a to x=a+h At x=a, $f(x) = (a+1)^2$ At x=a+h, $f(x) = (a+h+1)^2$ Net Change: $f(a+h) - f(a) = a^2 + h^2 + 1 + 2a + 2h + 2ah - (a^2 + 2a + 1) = h^2 + 2h + 2ah$ Average Rate of change: $\frac{f(a+h)- f(a)}{(a+h)-(a)} = \frac{h^2 + 2h + 2ah}{h} = h + 2 + 2a$
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