Answer
Domain: $(-\infty,\infty)$
Range: $(5,\infty)$
Work Step by Step
F is defined for all real numbers t.
Rewriting,
$F(t)=t^{2}+2t+1+4=(t+1)^{2}+5$
we see that the graph of $t^{2}$ is shifted left by one unit and raised by 5.
Therefore, the function $F(t) $ has a minimum value of 5.
So, the range of F is $(5,\infty)$
Domain: $(-\infty,\infty)$
Range: $(5,\infty)$
