Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 232: 16

Answer

Domain: $(-\infty, \frac{1}{2}) \cup (\frac{1}{2}, +\infty)$

Work Step by Step

The given rational function is defined for real numbers $x$ except the x-value that will make the denominator equal to zero. To find the number that will make the denominator equal to 0, equate the denominator to zero, then solve the equation to obtain: $2x-1 = 0 \\2x=1 \\x=\frac{1}{2}$ Thus, the domain of $f$ is the set of real numbers except $\frac{1}{2}$. In interval notation, the domain is $(-\infty, \frac{1}{2}) \cup (\frac{1}{2}, +\infty)$.
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