Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.4 - Limits at Infinity; Limits of Sequences - 13.4 Exercises - Page 930: 32

Answer

Convergent with limit $15$

Work Step by Step

Given: $f(x)=\lim\limits_{n\to \infty} \dfrac{5}{n}[n+\dfrac{4}{n}\dfrac{n(n+1)}{2}]=\lim\limits_{n\to \infty} 5+ \lim\limits_{n\to \infty} \dfrac{10n^2+10n}{n^2}$ The sequence converges when the limit $\lim\limits_{n\to \infty} a_n$ exists and when the limit $\lim\limits_{n\to \infty} a_n$ does not exist, then sequence diverges. Here, we have $\lim\limits_{n\to \infty}a_n=\lim\limits_{n\to \infty} 5+ \lim\limits_{n\to \infty} \dfrac{10n^2+10n}{n^2}$ This gives: $\lim\limits_{n\to \infty}a_n=5+\lim\limits_{n\to \infty}\dfrac{10+10/n}{1}$ or, $=5+\dfrac{\lim\limits_{n\to \infty}(10)+\lim\limits_{n\to \infty}(10/n)}{\lim\limits_{n\to \infty} (1)}$ Thus, $a_n=15$ Hence, the sequence is convergent with limit $15$
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