Answer
Convergent, 0
Work Step by Step
$3^n$ is by definition increasing with no bound. So the value of that as n grows large is infinity and 1 divided by infinity is 0 limitwise. Therefore the sequence is also convergent.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 13 - Section 13.4 - Limits at Infinity; Limits of Sequences - 13.4 Exercises - Page 930: 27
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