Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.4 - Limits at Infinity; Limits of Sequences - 13.4 Exercises - Page 930: 28

Answer

$\lim_{n\to\infty}\dfrac{(-1)^{n}}{n}=0$

Work Step by Step

$a_{n}=\dfrac{(-1)^{n}}{n}$ $\lim_{n\to\infty}a_{n}=\lim_{n\to\infty}\dfrac{(-1)^{n}}{n}=...$ For every $n$, the numerator will always be $1$ or $-1$. But as $n$ approaches infinity, the denominator becomes very big and the sequence approaches $0$. $\lim_{n\to\infty}\dfrac{(-1)^{n}}{n}=0$
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