Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.1 - Finding Limits Numerically and Graphically - 13.1 Exercises - Page 905: 9

Answer

$-3$

Work Step by Step

$\lim _{x\rightarrow 2}\dfrac {x+1}{x-3}=\dfrac {2+1}{2-3}=-3 $
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