Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.1 - Finding Limits Numerically and Graphically - 13.1 Exercises - Page 905: 15

Answer

$-1$

Work Step by Step

$\lim _{x\rightarrow 3 ^{-}}\dfrac {x-3}{\left| x-3\right| }=\dfrac {-\left| x-3\right| }{\left| x-3\right| }=-1$
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