Answer
$0$
Work Step by Step
$\lim _{x\rightarrow \infty }\dfrac {x^{2}+1}{x^{4}-3x+6}=\lim _{x\rightarrow \infty }\dfrac {1+\dfrac {1}{x^{2}}}{x^{2}-\dfrac {3}{x}+\dfrac {6}{x^{2}}}=\dfrac {1}{x^{2}}=0$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 13 - Section 13.1 - Finding Limits Numerically and Graphically - 13.1 Exercises - Page 905: 18
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