Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Test - Page 892: 7

Answer

$a_1^2,a_2^2,a_3^2,...$ is a geometric sequence whose common ratio is $r^2$

Work Step by Step

$\frac{a_2}{a_1}=r$ $\frac{a_3}{a_2}=r$ ... $\frac{(a_2)^2}{(a_1)^2}=(\frac{a_2}{a_1})^2=r^2$ $\frac{(a_3)^2}{(a_2)^2}=(\frac{a_3}{a_2})^2=r^2$ ... $a_1^2,a_2^2,a_3^2,...$ is a geometric sequence whose common ratio is $r^2$
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