Answer
307 is the 6th term
Work Step by Step
$a_{n+1}=3a_{n} - n$, given that $a_{1} = 2$
2nd term = 3(2) - 1 = 5
3rd term = 3(5) - 2 = 13
4th term = 3(13) - 3 = 36
5th term = 3(36) - 4 = 104
6th term = 3(104) - 5 = 307
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 12 - Review - Test - Page 892: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
