Answer
(a) $a_n=(0.85)(1.24)^{n}$ (b) $3.09$ lb (c) Geometric.
Work Step by Step
(a) The weight sequence is geometric with $a_0=0.85$ and $r=1+0.24=1.24$, thus we have $a_n=a_0r^{n}=(0.85)(1.24)^{n}$
(b) With $n=6$, we have $a_6=(0.85)(1.24)^{6}=3.09$ lb
(c) Because $\frac{a_1}{a_0}=\frac{a_2}{a_1}=\frac{a_3}{a_2}=...=\frac{a_n}{a_{n-1}}=1.24$, the sequence is geometric.
